Gate questions CS - 2014
The value of a floating type variable is represented using the single-precision 32-bit format. IEEE 754 standard uses 1 bit for sign, 8 bits for the biased exponent, and 23 bits for mantissa. A float type variable is assigned the decimal value of -14.25. The representation of X in hexadecimal notation is
(A) C1640000H
(B) 416C0000H
(C) 416C0000H
(D) C16C0000H
You should know:
Before seeing the questions please follow the previous chapter: IEEE – 754
Solution:
Exponent is 3
# Because single precision is Exponent is excess 127.
So,
The number in hexadecimal notation is C1640000H,
So, option (A) is correct.
UGC NET questions CS – 2014-DEC
The range of representable normalized numbers in the floating-point binary fractional representation in a 32- bit word with 1-bit sign, 8-bit excess 128 biased exponent, and the 23-bit mantissa is
You should know:
Before seeing the questions please follow the previous chapter: IEEE – 754
Solution:
The smallest number will be E-128
Maximum or largest number will be
Range of representable normalized numbers:
So, option (D) is correct.
GATE questions CS – 2012
The decimal value 0.5 in IEEE single-precision format has
(A) fraction bits 000…000 and exponent value 0
(B) fraction bits 000…000and exponent value -1
(C) fraction bits 100…000 and exponent value 0
(D) no exact representation
You should know:
Before seeing the questions please follow the previous chapter: IEEE – 754
Solution:
So, fraction bits or mantissa will be 000…000 and exponent value -1.
So, option (B) is correct.
Moreover, its representation in 32 – bits format will be.
Biased exponent = -1+127 = 126
(Because single precision is Exponent is excess 127)
And its hexadecimal representation will be