FOR FREE YEAR SOLVED
Exercise – A
1. Price of Type – I wheat = Rs 3.40 per kg. here in unit A/B, A is the Rs and B is the kg
The ratio must be of B only.
So, here we can be able to find the ratio of B.
Price of Type – II wheat = Rs 3.90 per kg.
Type – I and Type – II are mixed in a certain proportion such that the net worth becomes Rs 3.55 per kg
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0.45 : 0.15 = 3 : 1
3 : 1 is the required ratio of weight.
Option (d)
2. Type – I tea → Price = Rs 13 per kg
Type – II tea → Price = Rs 17 per kg
After mixing, net price = Rs 16 per kg.
So, after the allegation, we will get the ratio of weights.
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Hence, 1 : 3 is the required ratio of weight.
Option (b)
3. Similar to the previous sums
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Ans: 3 : 4
Option (d)
4. Option (a)
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5. Option (c)
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6. Option (a)
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7. Option (d)
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8. Option (b)
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9. Option (a)
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10. The SP of the mixture is 63 paise per kg.
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That means, if CP is 8 paise, then the gain is 1 paise.
Therefore SP = CP + Gain = 8 paise + 1 paise = 9 paise
If 9 paise (SP) is equivalent to 63 paise (SP).
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CP of Type – I sugar = 74 paise per kg
CP of Type – II sugar = 50 paise per kg
And,
CP of Type (I + II) sugar mixture = 56 paise per kg
Option (a)
11. Here we don’t have to find the ratio but the number which is mean or weighted average. That means, the figure obtained after mixing two entities in a proportion.
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The price of the mixture
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Option (d)
12. SP of mixture = Rs 8
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When CP = Rs 7 then gain = Rs 1
So, SP = CP + Gain / Profit = Rs 7 + Rs 1
Given, SP = Rs 8, So, CP of the mixture = Rs 7
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Option (a)
13. Here the price of wine only is Rs 20 a litre.
Water is mixed to it and the price got reduced because the volume of wine in a litre decreases. And we all know, there is no price for water. So, the price of water will Rs 0 a litre.
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Option (b)
14. Total weight of the mixture is 17 kg in which the ratio between currents of price Rs 51 and Rs 91 is 1 : 1.
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Option (b)
15. The 60 quintal mixture of two qualities rice has the cost of Rs 4652.50.
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or, 1875 : 2625
Dividing by 125
15 : 21
Dividing by 3
5 : 7
That means, 60 quintals of rice is present in 5 : 7 ratio of its quality.
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Option (a)
16. Equal quantities means 1 : 1 ratio
So,
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Net price of the mixture according to the quantity ratio =
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Now water which is priceless (i.e. price = Rs 0) is mixed with it to obtain a 50 litres mixture of worth Rs 16 a litre.
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Quantity ratio of mixture = Initial Mixture : Water = 4 : 1
In 50 litres, 40 litres is initial mixture. 10 litres is water.
Option (b)
Exercise – B
1. CP of the mixture would be
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SP of mixture when gain % is 25%
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But in the four options, no perfect answer (27.1875) is present. And in the question, APPROXIMATELY is given.
So, we have to choose the closest option.
Option (b)
2. CP of the mixture would be
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SP of mixture , given profit is 30%
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= Rs 16.38 per kg
Closest option is Option (a) – Rs 16.30
3. SP of the mixture, when profit is 20%
= Rs 18.6
CP of the mixture would be
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Option (d)
4. CP of the mixture would be
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= Rs 18.40 per kg
Option (c)
5. Gain% = 25%
SP = Rs 1.60/kg
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= Rs 1.28/kg
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Option (b)
6. Gain% = 20%
SP = Rs 5.20/kg
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Option (d)
7. Gain% = 25%
SP = Rs 0.60/kg
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So, Salt I : Salt II = 7 : 8
The quantity of salt II given is 16 kg.
So, x : 16 = 7 : 8
Where ‘x’ is the quantity of Salt I.
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Option (a)
8. Option (d)
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9. CP of the mixture
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SP of the mixture (Gain% = 20%)
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Option (b)
